x^2+35x+96=0

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Solution for x^2+35x+96=0 equation: 



x^2+35x+96=0

a = 1; b = 35; c = +96;
Δ = b2-4ac
Δ = 352-4·1·96
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-29}{2*1}=\frac{-64}{2}
=-32
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+29}{2*1}=\frac{-6}{2}
=-3
$

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